universal-life-protocol-core/crt-module.js

Revolutionary AI framework implementing living, conscious digital reality with meta-cognitive reasoning, attention economics, and autonomous learning

/**
 * Provides functions for multi-domain state resolution and harmonic resonance detection.
 * NOTE: This is a simplified implementation. A production system would use a BigInt library.
 */
export class CrtModule {
    /**
     * Solves a system of congruences x ≡ a_i (mod n_i) to find the unique Universal Counter N.
     * @param congruences An array of [address, base] pairs, e.g., [[A_1, B_1], [A_2, B_2]].
     * @returns The smallest non-negative integer solution for N.
     */
    static solve(congruences) {
        const product = congruences.reduce((acc, [, base]) => acc * BigInt(base), 1n);
        let sum = 0n;
        for (const [address, base] of congruences) {
            const bigBase = BigInt(base);
            const partialProduct = product / bigBase;
            const inverse = this.multiplicativeInverse(partialProduct, bigBase);
            sum += BigInt(address) * partialProduct * inverse;
        }
        return Number(sum % product);
    }
    /**
     * Checks for a harmonic resonance event, which occurs if an entity's address aligns
     * across multiple specified domains, often at a zero-state.
     * @param states A map of an entity's current states across different domains.
     * @param targetDomains An array of domain names (e.g., 'daily_cycle', 'weekly_cycle').
     * @param targetAddress The address to check for alignment (typically 0).
     * @returns True if all target domains are at the target address.
     */
    static checkHarmonicResonance(states, targetDomains, targetAddress = 0) {
        return targetDomains.every(domainId => {
            const state = states.get(domainId);
            return state && state.A === targetAddress;
        });
    }
    // Extended Euclidean Algorithm for modular multiplicative inverse with BigInts.
    static multiplicativeInverse(a, m) {
        const b = a % m;
        for (let x = 1n; x < m; x++) {
            if ((b * x) % m === 1n) {
                return x;
            }
        }
        return 1n;
    }
}
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