temporeest
Version:
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Markdown
To support:
```sql
select artistId, count(*) from album group by artistId order by count(*) desc
```
```ts
aritst.queryAll().orderBy(a => a.queryAlbums().count());
```
Ordering by a query from the source would just be a join?
It is:
1. An aggregation via grouping against the source id
2. an ordering by the count
```sql
select artist.*, count(*) from artist join album on album.artistId = artist.id group by artist.id order by count(*)
```
```ts
artist.queryAll().wantData().queryAlbums().count()
```
to get the artists + their album count.
simpler example:
```ts
artist.queryAll().wantData().queryAlbums().gen()
```
result:
```sql
select artist.*, album.* from artist join album on album.artistId = artist.id
```