sync-request-curl/dist/esm/utils.js

Fast way to send synchronous web requests in NodeJS. API is a subset of sync-request. Leverages node-libcurl for high performance. Cannot be used in a browser.

import { CurlCode } from 'node-libcurl';
export const handleQs = (url, qs) => {
    const urlObj = new URL(url);
    Object.entries(qs).forEach(([key, value]) => {
        if (Array.isArray(value)) {
            urlObj.searchParams.delete(key);
            value.forEach((item, i) => urlObj.searchParams.append(`${key}[${i}]`, String(item)));
        }
        else if (value === null) {
            urlObj.searchParams.set(key, '');
        }
        else if (value !== undefined) {
            urlObj.searchParams.set(key, String(value));
        }
    });
    urlObj.search = urlObj.searchParams.toString();
    return urlObj.href;
};
export const parseIncomingHeaders = (headers) => {
    return headers
        ? Object.entries(headers)
            .filter(([_, value]) => value !== undefined)
            .map(([key, value]) => value === '' ? `${key};` : `${key}: ${value}`)
        : [];
};
export const parseReturnedHeaders = (headerLines) => {
    return headerLines.reduce((acc, header) => {
        const [name, ...values] = header.split(':');
        if (name && values.length > 0) {
            acc[name.trim()] = values.join(':').trim();
        }
        return acc;
    }, {});
};
export const checkValidCurlCode = (code, method, url, options) => {
    if (code !== CurlCode.CURLE_OK) {
        throw new Error(`
      Curl request failed with code ${code}
      Please look up libcurl error code!
        - https://curl.se/libcurl/c/libcurl-errors.html

      DEBUG: {
        method: "${method}",
        url: "${url}",
        options: ${JSON.stringify(options)}
      }
    `);
    }
};
export const checkGetBodyStatus = (statusCode, body) => {
    if (statusCode >= 300) {
        throw new Error(`
      Server responded with status code ${statusCode}

      Body: ${body.toString()}

      Use 'res.body' instead of 'res.getBody()' to not have any errors thrown.
      The status code (in this case, ${statusCode}) can be checked manually with res.statusCode.
    `);
    }
};
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