react-drawing-board
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Browser drawing board created with canvas and React.
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text/typescript
import { MouseEvent as ReactMouseEvent } from 'react';
import { ViewMatrix } from './SketchPad';
export function matrix_invert(M: any) {
// I use Guassian Elimination to calculate the inverse:
// (1) 'augment' the matrix (left) by the identity (on the right)
// (2) Turn the matrix on the left into the identity by elemetry row ops
// (3) The matrix on the right is the inverse (was the identity matrix)
// There are 3 elemtary row ops: (I combine b and c in my code)
// (a) Swap 2 rows
// (b) Multiply a row by a scalar
// (c) Add 2 rows
//if the matrix isn't square: exit (error)
if (M.length !== M[0].length) {
return;
}
//create the identity matrix (I), and a copy (C) of the original
var i = 0,
ii = 0,
j = 0,
dim = M.length,
e = 0,
t = 0;
var I: any = [],
C: any = [];
for (i = 0; i < dim; i += 1) {
// Create the row
I[I.length] = [];
C[C.length] = [];
for (j = 0; j < dim; j += 1) {
//if we're on the diagonal, put a 1 (for identity)
if (i == j) {
I[i][j] = 1;
} else {
I[i][j] = 0;
}
// Also, make the copy of the original
C[i][j] = M[i][j];
}
}
// Perform elementary row operations
for (i = 0; i < dim; i += 1) {
// get the element e on the diagonal
e = C[i][i];
// if we have a 0 on the diagonal (we'll need to swap with a lower row)
if (e == 0) {
//look through every row below the i'th row
for (ii = i + 1; ii < dim; ii += 1) {
//if the ii'th row has a non-0 in the i'th col
if (C[ii][i] != 0) {
//it would make the diagonal have a non-0 so swap it
for (j = 0; j < dim; j++) {
e = C[i][j]; //temp store i'th row
C[i][j] = C[ii][j]; //replace i'th row by ii'th
C[ii][j] = e; //repace ii'th by temp
e = I[i][j]; //temp store i'th row
I[i][j] = I[ii][j]; //replace i'th row by ii'th
I[ii][j] = e; //repace ii'th by temp
}
//don't bother checking other rows since we've swapped
break;
}
}
//get the new diagonal
e = C[i][i];
//if it's still 0, not invertable (error)
if (e == 0) {
return;
}
}
// Scale this row down by e (so we have a 1 on the diagonal)
for (j = 0; j < dim; j++) {
C[i][j] = C[i][j] / e; //apply to original matrix
I[i][j] = I[i][j] / e; //apply to identity
}
// Subtract this row (scaled appropriately for each row) from ALL of
// the other rows so that there will be 0's in this column in the
// rows above and below this one
for (ii = 0; ii < dim; ii++) {
// Only apply to other rows (we want a 1 on the diagonal)
if (ii == i) {
continue;
}
// We want to change this element to 0
e = C[ii][i];
// Subtract (the row above(or below) scaled by e) from (the
// current row) but start at the i'th column and assume all the
// stuff left of diagonal is 0 (which it should be if we made this
// algorithm correctly)
for (j = 0; j < dim; j++) {
C[ii][j] -= e * C[i][j]; //apply to original matrix
I[ii][j] -= e * I[i][j]; //apply to identity
}
}
}
//we've done all operations, C should be the identity
//matrix I should be the inverse:
return I;
}
export const mapClientToCanvas = (
evt: {
clientX: number;
clientY: number;
},
canvas: HTMLCanvasElement,
viewMatrix: number[],
): [number, number] => {
const { top, left } = canvas.getBoundingClientRect();
const [a, b, c, d, e, f] = viewMatrix;
let x = evt.clientX - left;
let y = evt.clientY - top;
const inverse = matrix_invert([
[a, c, e],
[b, d, f],
[0, 0, 1],
]);
return [
inverse[0][0] * x + inverse[0][1] * y + inverse[0][2],
inverse[1][0] * x + inverse[1][1] * y + inverse[1][2],
];
};
export const matrix_multiply = (
[a1, b1, c1, d1, e1, f1]: number[],
[a2, b2, c2, d2, e2, f2]: number[],
) => {
return [
a1 * a2 + c1 * b2,
d1 * b2 + b1 * a2,
a1 * c2 + c1 * d2,
b1 * c2 + d1 * d2,
a1 * e2 + c1 * f2 + e1,
b1 * e2 + d1 * f2 + f1,
];
};
export const extract_scale_from_matrix = (viewMatrix: ViewMatrix) => {
return viewMatrix[0];
};
export const detectMobileDevice = () => {
return /Android|webOS|iPhone|iPad|iPod|BlackBerry|IEMobile|Opera Mini/i.test(navigator.userAgent);
};
export const isMobileDevice = detectMobileDevice();