mathmlben
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Visualization for goldstandard
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text/mathml
<math
xmlns="http://www.w3.org/1998/Math/MathML" display="block" alttext="Start 2 By 3 Matrix 1st Row 1st Column j 1 2nd Column j 2 3rd Column j 3 2nd Row 1st Column one-half 2nd Column j 3 minus one-half 3rd Column j 2 minus one-half EndMatrix equals left-parenthesis negative 1 right-parenthesis Superscript upper J Baseline left-parenthesis StartFraction left-parenthesis j 2 plus j 3 minus j 1 right-parenthesis left-parenthesis j 1 plus j 2 plus j 3 plus 1 right-parenthesis Over 2 j 2 left-parenthesis 2 j 2 plus 1 right-parenthesis 2 j 3 left-parenthesis 2 j 3 plus 1 right-parenthesis EndFraction right-parenthesis Superscript one-half">
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<mo data-semantic-type="operator" data-semantic-role="addition" data-semantic-id="104" data-semantic-parent="113" data-semantic-operator="infixop,+">+</mo>
<mn data-semantic-type="number" data-semantic-role="integer" data-semantic-font="normal" data-semantic-id="105" data-semantic-parent="113">1</mn>
</mrow>
<mo stretchy="false" data-semantic-type="fence" data-semantic-role="close" data-semantic-id="106" data-semantic-parent="114" data-semantic-operator="fenced">)</mo>
</mrow>
</mrow>
</mfrac>
</mrow>
<mo data-semantic-type="fence" data-semantic-role="close" data-semantic-id="122" data-semantic-parent="123" data-semantic-operator="fenced">)</mo>
</mrow>
<mrow class="MJX-TeXAtom-ORD">
<mfrac data-semantic-type="fraction" data-semantic-role="vulgar" data-semantic-id="126" data-semantic-children="124,125" data-semantic-parent="127">
<mn data-semantic-type="number" data-semantic-role="integer" data-semantic-font="normal" data-semantic-id="124" data-semantic-parent="126">1</mn>
<mn data-semantic-type="number" data-semantic-role="integer" data-semantic-font="normal" data-semantic-id="125" data-semantic-parent="126">2</mn>
</mfrac>
</mrow>
</msup>
</mrow>
</mrow>
<annotation encoding="application/x-tex">{\begin{Bmatrix}j_{1}&j_{2}&j_{3}\\{\frac {1}{2}}&j_{3}-{\frac {1}{2}}&j_{2}-{\frac {1}{2}}\end{Bmatrix}}=(-1)^{J}\left({\frac {(j_{2}+j_{3}-j_{1})(j_{1}+j_{2}+j_{3}+1)}{2j_{2}(2j_{2}+1)2j_{3}(2j_{3}+1)}}\right)^{\frac {1}{2}}</annotation>
</semantics>
</math>