javascript-algorithms-and-data-structures
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Algorithms and data-structures implemented on JavaScript
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JavaScript
import Sort from '../Sort';
// Using charCode (a = 97, b = 98, etc), we can map characters to buckets from 0 - 25
const BASE_CHAR_CODE = 97;
const NUMBER_OF_POSSIBLE_DIGITS = 10;
const ENGLISH_ALPHABET_LENGTH = 26;
export default class RadixSort extends Sort {
/**
* @param {*[]} originalArray
* @return {*[]}
*/
sort(originalArray) {
// Assumes all elements of array are of the same type
const isArrayOfNumbers = this.isArrayOfNumbers(originalArray);
let sortedArray = [...originalArray];
const numPasses = this.determineNumPasses(sortedArray);
for (let currentIndex = 0; currentIndex < numPasses; currentIndex += 1) {
const buckets = isArrayOfNumbers ?
this.placeElementsInNumberBuckets(sortedArray, currentIndex) :
this.placeElementsInCharacterBuckets(sortedArray, currentIndex, numPasses);
// Flatten buckets into sortedArray, and repeat at next index
sortedArray = buckets.reduce((acc, val) => {
return [...acc, ...val];
}, []);
}
return sortedArray;
}
/**
* @param {*[]} array
* @param {number} index
* @return {*[]}
*/
placeElementsInNumberBuckets(array, index) {
// See below. These are used to determine which digit to use for bucket allocation
const modded = 10 ** (index + 1);
const divided = 10 ** index;
const buckets = this.createBuckets(NUMBER_OF_POSSIBLE_DIGITS);
array.forEach((element) => {
this.callbacks.visitingCallback(element);
if (element < divided) {
buckets[0].push(element);
} else {
/**
* Say we have element of 1,052 and are currently on index 1 (starting from 0). This means
* we want to use '5' as the bucket. `modded` would be 10 ** (1 + 1), which
* is 100. So we take 1,052 % 100 (52) and divide it by 10 (5.2) and floor it (5).
*/
const currentDigit = Math.floor((element % modded) / divided);
buckets[currentDigit].push(element);
}
});
return buckets;
}
/**
* @param {*[]} array
* @param {number} index
* @param {number} numPasses
* @return {*[]}
*/
placeElementsInCharacterBuckets(array, index, numPasses) {
const buckets = this.createBuckets(ENGLISH_ALPHABET_LENGTH);
array.forEach((element) => {
this.callbacks.visitingCallback(element);
const currentBucket = this.getCharCodeOfElementAtIndex(element, index, numPasses);
buckets[currentBucket].push(element);
});
return buckets;
}
/**
* @param {string} element
* @param {number} index
* @param {number} numPasses
* @return {number}
*/
getCharCodeOfElementAtIndex(element, index, numPasses) {
// Place element in last bucket if not ready to organize
if ((numPasses - index) > element.length) {
return ENGLISH_ALPHABET_LENGTH - 1;
}
/**
* If each character has been organized, use first character to determine bucket,
* otherwise iterate backwards through element
*/
const charPos = index > element.length - 1 ? 0 : element.length - index - 1;
return element.toLowerCase().charCodeAt(charPos) - BASE_CHAR_CODE;
}
/**
* Number of passes is determined by the length of the longest element in the array.
* For integers, this log10(num), and for strings, this would be the length of the string.
*/
determineNumPasses(array) {
return this.getLengthOfLongestElement(array);
}
/**
* @param {*[]} array
* @return {number}
*/
getLengthOfLongestElement(array) {
if (this.isArrayOfNumbers(array)) {
return Math.floor(Math.log10(Math.max(...array))) + 1;
}
return array.reduce((acc, val) => {
return val.length > acc ? val.length : acc;
}, -Infinity);
}
/**
* @param {*[]} array
* @return {boolean}
*/
isArrayOfNumbers(array) {
// Assumes all elements of array are of the same type
return this.isNumber(array[0]);
}
/**
* @param {number} numBuckets
* @return {*[]}
*/
createBuckets(numBuckets) {
/**
* Mapping buckets to an array instead of filling them with
* an array prevents each bucket from containing a reference to the same array
*/
return new Array(numBuckets).fill(null).map(() => []);
}
/**
* @param {*} element
* @return {boolean}
*/
isNumber(element) {
return Number.isInteger(element);
}
}