functional-javascript-workshop/exercises/function_call/problem.md

The basics of functional programming in JavaScript. No libraries required.

# Task

Write a function that allows you to use `Array.prototype.slice` without using `slice.call` or `slice.apply` to invoke it.

Normally you have to use `slice` with `call` or `apply`:

```js
var slice = Array.prototype.slice

function() {
  var args = slice.call(arguments) // this works
}
```

We want this to work:

```js
var slice = yourFunction

function() {
  var args = slice(arguments) // this works
}
```

## Example

A function, `slice` that exhibits the following behaviour:

```js
var nums = [1,2,3,4,5]

// your slice function should match the regular
// behaviour of slice, except it takes the array
// as the first argument

slice(nums, 0, 2) // [1, 2]
slice(nums, 1, 2) // [2]

// regular slice usage for comparison
nums.slice(0, 2) // [1, 2]
nums.slice(1, 2) // [2]
```

## Conditions

* Do not use any for/while loops or Array#forEach.
* Do not use the `function` keyword :D

## Hints

* This is absolutely a one liner.
* Every JavaScript Function inherits methods such as call, apply and bind from the object `Function.prototype`.
* Function#call executes the value of `this` when it is invoked.  Inside `someFunction.call()`, the value of `this` will be `someFunction`.
* Function.call itself is a function thus it inherits from `Function.prototype`

```js
function myFunction() {
  console.log('called my function')
}

Function.prototype.call.call(myFunction) // => "called my function"
```

## Boilerplate

```js
module.exports = // your solution here!
```