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# Delete Node in a BST > Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview. Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: 1. Search for a node to remove. 2. If the node is found, delete the node. **Follow up:** Can you solve it with time complexity `O(height of tree)`? **Example 1:** ![](https://assets.leetcode.com/uploads/2020/09/04/del_node_1.jpg) **Input:** root = \[5,3,6,2,4,null,7\], key = 3 **Output:** \[5,4,6,2,null,null,7\] **Explanation:** Given key to delete is 3. So we find the node with value 3 and delete it. One valid answer is \[5,4,6,2,null,null,7\], shown in the above BST. Please notice that another valid answer is \[5,2,6,null,4,null,7\] and it's also accepted. ![](https://assets.leetcode.com/uploads/2020/09/04/del_node_supp.jpg) **Example 2:** **Input:** root = \[5,3,6,2,4,null,7\], key = 0 **Output:** \[5,3,6,2,4,null,7\] **Explanation:** The tree does not contain a node with value = 0. **Example 3:** **Input:** root = \[\], key = 0 **Output:** \[\] **Constraints:** * The number of nodes in the tree is in the range `[0, 104]`. * `-105 <= Node.val <= 105` * Each node has a **unique** value. * `root` is a valid binary search tree. * `-105 <= key <= 105` [Source](https://leetcode.com/problems/delete-node-in-a-bst/)