dist-javascript-algorithms-and-data-structures
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Algorithms and data-structures implemented on JavaScript
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JavaScript
;
Object.defineProperty(exports, "__esModule", {
value: true
});
exports.default = void 0;
var _Sort = _interopRequireDefault(require("../Sort"));
function _interopRequireDefault(obj) { return obj && obj.__esModule ? obj : { default: obj }; }
class CountingSort extends _Sort.default {
/**
* @param {number[]} originalArray
* @param {number} [smallestElement]
* @param {number} [biggestElement]
*/
sort(originalArray, smallestElement = undefined, biggestElement = undefined) {
// Init biggest and smallest elements in array in order to build number bucket array later.
let detectedSmallestElement = smallestElement || 0;
let detectedBiggestElement = biggestElement || 0;
if (smallestElement === undefined || biggestElement === undefined) {
originalArray.forEach(element => {
// Visit element.
this.callbacks.visitingCallback(element); // Detect biggest element.
if (this.comparator.greaterThan(element, detectedBiggestElement)) {
detectedBiggestElement = element;
} // Detect smallest element.
if (this.comparator.lessThan(element, detectedSmallestElement)) {
detectedSmallestElement = element;
}
});
} // Init buckets array.
// This array will hold frequency of each number from originalArray.
const buckets = Array(detectedBiggestElement - detectedSmallestElement + 1).fill(0);
originalArray.forEach(element => {
// Visit element.
this.callbacks.visitingCallback(element);
buckets[element - detectedSmallestElement] += 1;
}); // Add previous frequencies to the current one for each number in bucket
// to detect how many numbers less then current one should be standing to
// the left of current one.
for (let bucketIndex = 1; bucketIndex < buckets.length; bucketIndex += 1) {
buckets[bucketIndex] += buckets[bucketIndex - 1];
} // Now let's shift frequencies to the right so that they show correct numbers.
// I.e. if we won't shift right than the value of buckets[5] will display how many
// elements less than 5 should be placed to the left of 5 in sorted array
// INCLUDING 5th. After shifting though this number will not include 5th anymore.
buckets.pop();
buckets.unshift(0); // Now let's assemble sorted array.
const sortedArray = Array(originalArray.length).fill(null);
for (let elementIndex = 0; elementIndex < originalArray.length; elementIndex += 1) {
// Get the element that we want to put into correct sorted position.
const element = originalArray[elementIndex]; // Visit element.
this.callbacks.visitingCallback(element); // Get correct position of this element in sorted array.
const elementSortedPosition = buckets[element - detectedSmallestElement]; // Put element into correct position in sorted array.
sortedArray[elementSortedPosition] = element; // Increase position of current element in the bucket for future correct placements.
buckets[element - detectedSmallestElement] += 1;
} // Return sorted array.
return sortedArray;
}
}
exports.default = CountingSort;