cypress-upload-file-post-form
Version:
Solution for two Cypress testing use-cases I came across with: perform a direct http FORM request to the server containing a file and other parameters and upload a file into a form before submission
54 lines (50 loc) • 1.77 kB
JavaScript
// ***********************************************
// This example commands.js shows you how to
// create various custom commands and overwrite
// existing commands.
//
// For more comprehensive examples of custom
// commands please read more here:
// https://on.cypress.io/custom-commands
// ***********************************************
//
//
// -- This is a parent command --
// Cypress.Commands.add("login", (email, password) => { ... })
//
//
// -- This is a child command --
// Cypress.Commands.add("drag", { prevSubject: 'element'}, (subject, options) => { ... })
//
//
// -- This is a dual command --
// Cypress.Commands.add("dismiss", { prevSubject: 'optional'}, (subject, options) => { ... })
//
//
// -- This is will overwrite an existing command --
// Cypress.Commands.overwrite("visit", (originalFn, url, options) => { ... })
Cypress.Commands.add('upload_file', (fileName, fileType = ' ', selector) => {
cy.get(selector).then(subject => {
cy.fixture(fileName, 'base64')
.then(Cypress.Blob.base64StringToBlob)
.then(blob => {
const el = subject[0]
const testFile = new File([blob], fileName, { type: fileType })
const dataTransfer = new DataTransfer()
dataTransfer.items.add(testFile)
el.files = dataTransfer.files
})
})
})
// Performs an XMLHttpRequest instead of a cy.request (able to send data as FormData - multipart/form-data)
Cypress.Commands.add('form_request', (method, url, formData, done) => {
const xhr = new XMLHttpRequest();
xhr.open(method, url);
xhr.onload = function () {
done(xhr);
};
xhr.onerror = function () {
done(xhr);
};
xhr.send(formData);
})