coffee-script
Version:
Unfancy JavaScript
222 lines (145 loc) • 4.48 kB
text/coffeescript
nums = (n * n for n in [1, 2, 3] when n & 1)
results = (n * 2 for n in nums)
ok results.join(',') is '2,18'
obj = {one: 1, two: 2, three: 3}
names = (prop + '!' for prop of obj)
odds = (prop + '!' for prop, value of obj when value & 1)
ok names.join(' ') is "one! two! three!"
ok odds.join(' ') is "one! three!"
nums = (i * 3 for i in [1..3])
negs = (x for x in [-20..-5*2])
negs = negs[0..2]
result = nums.concat(negs).join(', ')
ok result is '3, 6, 9, -20, -19, -18'
results = (x for x in [0...15] by 5)
ok results.join(' ') is '0 5 10'
results = (x for x in [0..100] by 10)
ok results.join(' ') is '0 10 20 30 40 50 60 70 80 90 100'
results = (x for x in [5..1])
ok results.join(' ') is '5 4 3 2 1'
ok results.join(' ') is [(10-5)..(-2+3)].join(' ')
results = (x for x in [10..1])
ok results.join(' ') is [10..1].join(' ')
results = (x for x in [10...0] by -2)
ok results.join(' ') is [10, 8, 6, 4, 2].join(' ')
eq "#{i for i in [5..1]}", '5,4,3,2,1'
eq "#{i for i in [5..-5] by -5}", '5,0,-5'
a = 6
b = 0
c = -2
eq "#{i for i in [a..b]}", '6,5,4,3,2,1,0'
eq "#{i for i in [a..b] by c}", '6,4,2,0'
evens = for num in [1, 2, 3, 4, 5, 6] when not (num & 1)
num *= -1
num -= 2
num * -1
eq evens + '', '4,6,8'
ok 2 of evens
all = 1
obj = {}
for method in ['one', 'two', 'three']
obj[method] = ->
"I'm " + method
ok obj.one() is "I'm one"
ok obj.two() is "I'm two"
ok obj.three() is "I'm three"
i = 0
for i in [1..3]
-> 'func'
break if false
ok i is 4
funcs = for i in [1..3]
-> -i
ok (func() for func in funcs).join(' ') is '-1 -2 -3'
ok i is 4
# Even when referenced in the filter.
list = ['one', 'two', 'three']
methods = for num, i in list when num isnt 'two' and i isnt 1
-> num + ' ' + i
ok methods.length is 2
ok methods[0]() is 'one 0'
ok methods[1]() is 'three 2'
funcs = []
for i in [1..3]
x = i * 2
((z)->
funcs.push -> z + ' ' + i
)(x)
ok (func() for func in funcs).join(', ') is '2 1, 4 2, 6 3'
funcs = []
results = for i in [1..3]
z = (x * 3 for x in [1..i])
((a, b, c) -> [a, b, c].join(' ')).apply this, z
ok results.join(', ') is '3 , 3 6 , 3 6 9'
array = [0..10]
ok(num % 2 is 0 for num in array by 2)
multiLiner =
for x in [3..5]
for y in [3..5]
[]
singleLiner =
(([x, y] for y in [3..5]) for x in [3..5])
ok multiLiner.length is singleLiner.length
ok 5 is multiLiner[2][2][1]
ok 5 is singleLiner[2][2][1]
result = null
store = (obj) -> result = obj
store (x * 2 for x in [3, 2, 1])
ok result.join(' ') is '6 4 2'
# Closure-wrapped comprehensions that refer to the "arguments" object.
expr = ->
result = (item * item for item in arguments)
ok expr(2, 4, 8).join(' ') is '4 16 64'
# Fast object comprehensions over all properties, including prototypal ones.
class Cat
constructor: -> @name = 'Whiskers'
breed: 'tabby'
hair: 'cream'
whiskers = new Cat
own = (value for key, value of whiskers)
all = (value for all key, value of whiskers)
ok own.join(' ') is 'Whiskers'
ok all.sort().join(' ') is 'Whiskers cream tabby'
exxes = ('x' for [0...10])
ok exxes.join(' ') is 'x x x x x x x x x x'
rule = (x) -> x
learn = ->
rule for rule in [1, 2, 3]
ok learn().join(' ') is '1 2 3'
ok rule(101) is 101
f = -> [-> ok no, 'should cache source']
ok yes for k of [f] = f()
val = for i in [1]
for j in [] then break
i
ok val[0] is i
func = -> for i in [1]
break if i is 2
j for j in [1]
ok func()[0][0] is 1
i = 6
odds = while i--
continue unless i & 1
i
ok odds.join(', ') is '5, 3, 1'