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abbott-methods

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abbott,methods,method,functions,function

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/** * @description 得到两个数组的并集 * @param {[]} arrayAny1 * @param {[]} arrayAny2 */ export const arrayUnion = (arrayAny1: any[], arrayAny2: any[]) => { return Array.from(new Set([...arrayAny1, ...arrayAny2])) }