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@oat-sa/tao-item-runner-qti

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define(['lodash'], function (_) { 'use strict'; _ = _ && Object.prototype.hasOwnProperty.call(_, 'default') ? _['default'] : _; /* * This program is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation; under version 2 * of the License (non-upgradable). * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA. * * Copyright (c) 2015-2019 (original work) Open Assessment Technlogies SA (under the project TAO-PRODUCT); * */ var lcmProcessor = { constraints: { minOperand: 1, lcmOperand: -1, cardinality: ['single', 'multiple', 'ordered'], baseType: ['integer'] }, operands: [], /** * Process operands and returns the lcm. * @type {OperatorProcessor} * @exports taoQtiItem/scoring/processor/expressions/operators/lcm */ process: function() { var result = { cardinality: 'single', baseType: 'integer' }; var castedOperands; //if at least one operand is null or infinity, then break and return null if (_.some(this.operands, _.isNull) === true) { return null; } castedOperands = this.preProcessor.parseOperands(this.operands); //if at least one operand is a not a number, then break and return null if (!castedOperands.every(this.preProcessor.isNumber)) { return null; } if (castedOperands.value().indexOf(0) !== -1) { result.value = 0; return result; } result.value = lcm(castedOperands.value()); return result; } }; /** * Calculates least common multiple for two ore more integers * @param {Array<number|Number>}numbers * @returns {number} least common multiple */ function lcm(numbers) { var n = numbers.length, a = Math.abs(numbers[0]), b, c, i; for (i = 1; i < n; i++) { b = Math.abs(numbers[i]); c = a; while (a && b) { a > b ? a %= b : b %= a; } a = Math.abs(c * numbers[i]) / (a + b); } return a; } return lcmProcessor; });