@attivio/suit
Version:
Attivio SUIT, the Search UI Toolkit, is a library for creating search clients for searching the Attivio platform.
58 lines (46 loc) • 2.14 kB
JavaScript
var _class, _temp;
function _classCallCheck(instance, Constructor) { if (!(instance instanceof Constructor)) { throw new TypeError("Cannot call a class as a function"); } }
function _possibleConstructorReturn(self, call) { if (!self) { throw new ReferenceError("this hasn't been initialised - super() hasn't been called"); } return call && (typeof call === "object" || typeof call === "function") ? call : self; }
function _inherits(subClass, superClass) { if (typeof superClass !== "function" && superClass !== null) { throw new TypeError("Super expression must either be null or a function, not " + typeof superClass); } subClass.prototype = Object.create(superClass && superClass.prototype, { constructor: { value: subClass, enumerable: false, writable: true, configurable: true } }); if (superClass) Object.setPrototypeOf ? Object.setPrototypeOf(subClass, superClass) : subClass.__proto__ = superClass; }
import React from 'react';
import SimilarAuthorCard from './SimilarAuthorCard';
var ExpertDetails = (_temp = _class = function (_React$Component) {
_inherits(ExpertDetails, _React$Component);
function ExpertDetails() {
_classCallCheck(this, ExpertDetails);
return _possibleConstructorReturn(this, _React$Component.apply(this, arguments));
}
ExpertDetails.prototype.render = function render() {
return React.createElement(
'dl',
{ className: 'attivio-labeldata-2col attivio-expert-details attivio-expert360-details' },
React.createElement(
'dt',
null,
'Title'
),
React.createElement(
'dd',
null,
this.props.expert.title
),
React.createElement(
'dt',
null,
React.createElement(
'abbr',
{ className: 'attivio-abbr', title: 'Department' },
'Dept'
)
),
React.createElement(
'dd',
null,
this.props.expert.department
)
);
};
return ExpertDetails;
}(React.Component), _class.displayName = 'ExpertDetails', _temp);
export { ExpertDetails as default };
ExpertDetails.ExpertInfo = SimilarAuthorCard.ExpertInfo;